(2y^2-7y+5)-(7y^2-7y+3)=

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Solution for (2y^2-7y+5)-(7y^2-7y+3)= equation:


Simplifying
(2y2 + -7y + 5) + -1(7y2 + -7y + 3) = 0

Reorder the terms:
(5 + -7y + 2y2) + -1(7y2 + -7y + 3) = 0

Remove parenthesis around (5 + -7y + 2y2)
5 + -7y + 2y2 + -1(7y2 + -7y + 3) = 0

Reorder the terms:
5 + -7y + 2y2 + -1(3 + -7y + 7y2) = 0
5 + -7y + 2y2 + (3 * -1 + -7y * -1 + 7y2 * -1) = 0
5 + -7y + 2y2 + (-3 + 7y + -7y2) = 0

Reorder the terms:
5 + -3 + -7y + 7y + 2y2 + -7y2 = 0

Combine like terms: 5 + -3 = 2
2 + -7y + 7y + 2y2 + -7y2 = 0

Combine like terms: -7y + 7y = 0
2 + 0 + 2y2 + -7y2 = 0
2 + 2y2 + -7y2 = 0

Combine like terms: 2y2 + -7y2 = -5y2
2 + -5y2 = 0

Solving
2 + -5y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5y2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5y2 = 0 + -2
-5y2 = 0 + -2

Combine like terms: 0 + -2 = -2
-5y2 = -2

Divide each side by '-5'.
y2 = 0.4

Simplifying
y2 = 0.4

Take the square root of each side:
y = {-0.632455532, 0.632455532}

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